In the conversion of a moving coil galvanometer into an ammeter of a required range,what is the resistance of the ammeter so formed? [$S$ = shunt resistance and $G$ = resistance of the galvanometer]

$A$ moving coil galvanometer of resistance $100 \,\Omega$ is used as an ammeter using a shunt resistance of $0.1 \,\Omega$. The maximum deflection current in the galvanometer is $100 \,\mu A$. Find the minimum current in the circuit so that the ammeter shows maximum deflection in $mA$.

$A$ galvanometer of resistance $100\,\Omega$ has $50$ divisions on its scale and a sensitivity of $20\,\mu A/\text{division}$. It is to be converted into a voltmeter with three ranges: $0-2\,V$,$0-10\,V$,and $0-20\,V$. The appropriate circuit to do so is:

Assertion: Voltmeter is connected in parallel with the circuit.
Reason: Resistance of a voltmeter is very large.

To convert a $800\, mV$ range millivoltmeter of resistance $40\,\Omega$ into an ammeter of $100\, mA$ range,the resistance to be connected as a shunt is .............. $\Omega$.

$A$ voltmeter of $250 mV$ range having a resistance of $10 \Omega$ is converted into an ammeter of $250 mA$ range. The value of the necessary shunt is (nearly): (in $\Omega$)